JoeCMath

Matrix Minors

This page follows the JoeCMath video Master Matrix Minors in 3 Minutes. The video defines the minor $M_{ij}$, then works through symbolic and numeric examples for a $3\times 3$ matrix.

Main Idea

The video treats a minor as a smaller determinant, not as a signed cofactor.

For a square matrix

\[A= \begin{bmatrix} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33} \end{bmatrix},\]

the minor of entry $a_{ij}$ is denoted $M_{ij}$. To find $M_{ij}$, delete row $i$ and column $j$, then take the determinant of what remains.

The index on a minor tells you which row and column to remove before taking the determinant.

Watch this section: minor of a square matrix at 0:00.

Finding $M_{11}$

The first worked setup in the video is $M_{11}$.

Start with

\[A= \begin{bmatrix} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33} \end{bmatrix}.\]

The subscript $11$ means delete row $1$ and column $1$.

After deleting that row and column, the remaining matrix is

\[\begin{bmatrix} a_{22} & a_{23} \\ a_{32} & a_{33} \end{bmatrix}.\]

So

\[M_{11}=\begin{vmatrix} a_{22} & a_{23} \\ a_{32} & a_{33} \end{vmatrix}.\]

Using the $2\times 2$ determinant rule,

\[\begin{vmatrix} a & b \\ c & d \end{vmatrix}=ad-bc,\]

we get

\[M_{11}=a_{22}a_{33}-a_{23}a_{32}.\]

Watch this section: finding the minor of entry $a_{11}$ at 0:17.

The Remaining Minors

The video then moves through the other minors for a $3\times 3$ matrix. Each one uses the same instruction: delete the row and column named by the subscript.

$M_{12}$: delete row $1$ and column $2$.

\[\begin{aligned} M_{12} &=\begin{vmatrix} a_{21} & a_{23} \\ a_{31} & a_{33} \end{vmatrix}\\ &=a_{21}a_{33}-a_{23}a_{31} \end{aligned}\]

$M_{13}$: delete row $1$ and column $3$.

\[\begin{aligned} M_{13} &=\begin{vmatrix} a_{21} & a_{22} \\ a_{31} & a_{32} \end{vmatrix}\\ &=a_{21}a_{32}-a_{22}a_{31} \end{aligned}\]

$M_{21}$: delete row $2$ and column $1$.

\[\begin{aligned} M_{21} &=\begin{vmatrix} a_{12} & a_{13} \\ a_{32} & a_{33} \end{vmatrix}\\ &=a_{12}a_{33}-a_{13}a_{32} \end{aligned}\]

$M_{22}$: delete row $2$ and column $2$.

\[\begin{aligned} M_{22} &=\begin{vmatrix} a_{11} & a_{13} \\ a_{31} & a_{33} \end{vmatrix}\\ &=a_{11}a_{33}-a_{13}a_{31} \end{aligned}\]

$M_{23}$: delete row $2$ and column $3$.

\[\begin{aligned} M_{23} &=\begin{vmatrix} a_{11} & a_{12} \\ a_{31} & a_{32} \end{vmatrix}\\ &=a_{11}a_{32}-a_{12}a_{31} \end{aligned}\]

$M_{31}$: delete row $3$ and column $1$.

\[\begin{aligned} M_{31} &=\begin{vmatrix} a_{12} & a_{13} \\ a_{22} & a_{23} \end{vmatrix}\\ &=a_{12}a_{23}-a_{13}a_{22} \end{aligned}\]

$M_{32}$: delete row $3$ and column $2$.

\[\begin{aligned} M_{32} &=\begin{vmatrix} a_{11} & a_{13} \\ a_{21} & a_{23} \end{vmatrix}\\ &=a_{11}a_{23}-a_{13}a_{21} \end{aligned}\]

$M_{33}$: delete row $3$ and column $3$.

\[\begin{aligned} M_{33} &=\begin{vmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{vmatrix}\\ &=a_{11}a_{22}-a_{12}a_{21} \end{aligned}\]

This section is less about memorizing all eight formulas and more about seeing the row-column deletion pattern over and over.

Watch this section: all eight remaining minors at 1:06.

Numeric Example: $M_{22}$

The first numeric matrix in the video is

\[A= \begin{bmatrix} 1 & 7 & 5 \\ 4 & 3 & 8 \\ 6 & 9 & 2 \end{bmatrix}.\]

To find $M_{22}$, delete row $2$ and column $2$.

That leaves

\[\begin{bmatrix} 1 & 5 \\ 6 & 2 \end{bmatrix}.\]

Now take the determinant:

\[M_{22}=\begin{vmatrix} 1 & 5 \\ 6 & 2 \end{vmatrix}.\]

Using $ad-bc$,

\[M_{22}=1\cdot 2-6\cdot 5=2-30=-28.\]

Deleting row $2$ and column $2$ leaves the corner entries from rows $1$ and $3$.

Watch this section: find $M_{22}$ of a $3\times 3$ matrix at 1:52.

Numeric Example: $M_{31}$

The second numeric example uses the same matrix:

\[A= \begin{bmatrix} 1 & 7 & 5 \\ 4 & 3 & 8 \\ 6 & 9 & 2 \end{bmatrix}.\]

To find $M_{31}$, delete row $3$ and column $1$.

That leaves

\[\begin{bmatrix} 7 & 5 \\ 3 & 8 \end{bmatrix}.\]

So

\[M_{31}=\begin{vmatrix} 7 & 5 \\ 3 & 8 \end{vmatrix}.\]

Then

\[M_{31}=7\cdot 8-3\cdot 5=56-15=41.\]

This example is a good reminder that the entry $a_{31}$ is not the value of the minor. It tells you what row and column to remove.

Watch this section: find $M_{31}$ of a $3\times 3$ matrix at 2:23.

Timestamp Guide

Section What is shown Video
Minor definition Define $M_{ij}$ by deleting row $i$ and column $j$. 0:00
$M_{11}$ setup Delete row $1$ and column $1$ from a symbolic $3\times 3$ matrix. 0:17
Remaining minors Work through the other symbolic minors. 1:06
Numeric $M_{22}$ Delete row $2$ and column $2$, then compute the $2\times 2$ determinant. 1:52
Numeric $M_{31}$ Delete row $3$ and column $1$, then compute the $2\times 2$ determinant. 2:23

Minors are one piece of cofactor expansion. For the next step, use the cofactor expansion companion guide.

You can also browse determinant notes or the JoeCMath linear algebra playlist: watch the playlist on YouTube.